Skip to main content
Skip to main content

What is Distance Between Point and Plane?

Visual representation of the shortest distance from a point to a plane
Visual representation of the shortest distance from a point to a plane

In 3D geometry, a plane is a flat, two-dimensional surface that extends infinitely in all directions. A point is a specific location in space. The distance between a point and a plane is the length of the shortest path connecting them, which is always a straight line that's perpendicular to the plane.

Why is this important? This concept helps us solve real-world problems like finding the shortest distance from a drone to the ground, determining how close a satellite is to Earth's orbital plane, or calculating distances in architecture and engineering.

The key to understanding this distance is the normal vector - an arrow perpendicular to the plane. The distance calculation uses this normal vector to find the shortest path.

How to Calculate the Distance

Infographic explaining the formula for distance from a point to a plane
Visual guide to the distance formula components

To calculate the distance between a point and a plane, we use a special formula. First, we need to know:

- The equation of the plane: ax + by + cz + d = 0 - The coordinates of the point: (x₀, y₀, z₀)

Distance Formula

distance = |ax₀ + by₀ + cz₀ + d| / √(a² + b² + c²)

This formula gives us the shortest distance from point (x₀, y₀, z₀) to the plane ax + by + cz + d = 0

Let's break down the formula:

- The numerator |ax₀ + by₀ + cz₀ + d| is the absolute value of the plane equation with the point's coordinates plugged in
- The denominator √(a² + b² + c²) is the length of the normal vector to the plane

This formula works because it calculates how far the point is from the plane along the perpendicular direction.

Step-by-Step Examples

Example calculation of distance from a point to a plane
Visual example showing distance calculation

Let's work through an example together to see how the formula works:

Example 1: Basic Calculation

Plane: 2x - 3y + 4z - 6 = 0

Point: (1, 2, 3)

Step 1: Identify a, b, c, d from the plane equation

a = 2, b = -3, c = 4, d = -6

Step 2: Plug the point into the numerator: |2(1) + (-3)(2) + 4(3) - 6|

= |2 - 6 + 12 - 6| = |2| = 2

Step 3: Calculate the denominator: √(2² + (-3)² + 4²)

= √(4 + 9 + 16) = √29 ≈ 5.385

Step 4: Divide: 2 / 5.385 ≈ 0.371

Answer: The distance is approximately 0.371 units

Example 2: Distance to Coordinate Plane

Plane: The xy-plane (z = 0)

Point: (4, -2, 5)

Step 1: Write the plane equation: 0x + 0y + 1z = 0 (so z = 0)

a = 0, b = 0, c = 1, d = 0

Step 2: Numerator: |0(4) + 0(-2) + 1(5) + 0| = |5| = 5

Step 3: Denominator: √(0² + 0² + 1²) = √1 = 1

Step 4: Distance = 5/1 = 5 units

This makes sense because the point is 5 units above the xy-plane!

Distance Calculation Quiz

Test your understanding with this 5-question quiz. Choose the correct answer for each question.

1. What does the normal vector represent?
2. For the plane 3x - 4y + z - 5 = 0, what is the normal vector?
3. What is the distance from point (1, 2, 3) to the plane x + y + z = 0?
4. Which of these represents the distance formula?
5. If a point is on the plane, what is its distance to the plane?

Frequently Asked Questions

Here are answers to common questions about distance to a plane:

Geometry Trivia

Discover interesting facts about geometry and measurement:

Copyright © 2025 Workybooks. Made with ♥ in California.